Subjects/Calculus II/A.10. Integrals with a+bu/FormulaA.10. Integrals with \(a + bu\)FormulaIn A.10. Integrals with a+buFormulaCopy LaTeX∫u(a+bu)2du=a(a+bu)1−a21lnua+bu+CVariablesCConstant real de integraciónuVariable auxiliar de sustituciónaConstant real (a menudo a>0)duDiferencial respecto de ulnLogaritmo naturalConditionslnua+bu+CRelated formulasRelatedFormula∫(a+bu)2udu=b2(a+bu)a+b21ln∣a+bu∣+COpen formulaOpen in sectionRelatedFormula∫(a+bu)2u2du=b31(a+bu−a+bua2−2aln∣a+bu∣)+COpen formulaOpen in sectionRelatedFormula∫u2(a+bu)du=−au1+a2blnua+bu+COpen formulaOpen in sectionRelatedA.10.2 With radicals a+bu∫ua+budu=15b22(3bu−2a)(a+bu)3/2+COpen formulaOpen in sectionRelatedFormula∫u(a+bu)du=a1lna+buu+COpen formulaOpen in sectionRelatedFormula∫a+buudu=3b22(bu−2a)a+bu+COpen formulaOpen in sectionRelatedFormula∫a+buu2du=2b31[(a+bu)2−4a(a+bu)+2a2ln∣a+bu∣]+COpen formulaOpen in sectionRelatedFormula∫a+buu2du=15b32(8a2+3b2u2−4abu)a+bu+COpen formulaOpen in section